122. Best Time to Buy and Sell Stock II 简单
Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times).
Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).
Example 1:
Input: [7,1,5,3,6,4]
Output: 7
Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.
Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.
Example 2:
Input: [1,2,3,4,5]
Output: 4
Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are
engaging multiple transactions at the same time. You must sell before buying again.
Example 3:
Input: [7,6,4,3,1]
Output: 0
Explanation: In this case, no transaction is done, i.e. max profit = 0.
class Solution {
public:
int maxProfit(vector<int>& prices) {
int len = prices.size();
int ans =0;
int i;
for(i = 1;i<len;++i){
if(prices[i]>prices[i-1]){
ans+=prices[i] - prices[i-1];
}
}
return ans;
}
};
2 comments
我靠,你还说我水文章,你自己不也把Easy的题往上写
我的目标是一个月后200道leetcode上的题,先要有数量才能有质量